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9x^2+29x+6=1
We move all terms to the left:
9x^2+29x+6-(1)=0
We add all the numbers together, and all the variables
9x^2+29x+5=0
a = 9; b = 29; c = +5;
Δ = b2-4ac
Δ = 292-4·9·5
Δ = 661
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{661}}{2*9}=\frac{-29-\sqrt{661}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{661}}{2*9}=\frac{-29+\sqrt{661}}{18} $
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